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Apple App-Development-with-Swift-Certified-User Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| App Lifecycle and Deployment Concepts | - Understanding app structure
|
| App Logic and Data Handling | - Data management in apps
|
| Introduction to App Development with Swift | - Swift programming fundamentals
|
| User Interface Development | - Building iOS interfaces
|
Apple App Development with Swift Certified User Sample Questions:
If View A calls View B, which Swift Property Wrapper would you use in View B in order to return the value of a state to View A?
- A. @Observable
- B. @Binding
- C. @Environment
- D. @State
Correct Answer: B 🗳️
Explanation: Only visible for Prep4sures members. You can sign-up / login (it's free).
Select the area in Xcode that allows you to display the Preview Canvas.
Correct Answer:

Explanation:
This question belongs to Xcode Developer Tools , specifically the objective domain on identifying and using the features of the Xcode interface . In the screenshot, the correct area is the upper-right corner of the editor toolbar , where Xcode provides the control for editor display options. Apple's documentation explains that to show previews, you can use the editor controls and specifically notes that you can click the Adjust Editor Options button and choose Preview , which displays the preview canvas to the right of the editor.
So, in hotspot terms, the correct selection is the editor options control near the top-right of the code editor
, not the Run button, not the Inspector, and not the Project navigator. This aligns with Apple's preview workflow for SwiftUI in Xcode, where the canvas is shown from the editor display controls. Apple also describes the preview canvas as part of Xcode's interface for quickly visualizing UI changes while editing code.

Review the code.
Note: You might need to scroll to see the entire block of code.
A breakpoint is set on line 3. When the application is run. it will stop at line 3. You need to debug the code.
Drag each debugging control from the left to the correct instruction on the right. You will receive partial credit for each correct answer
Correct Answer:

Explanation:
This question belongs to Xcode Developer Tools , especially the objective on using debugging techniques including breakpoints and stepping controls .
When execution stops at a breakpoint on line 3, Step Over runs that line without entering into another function call, so it is the correct action for moving past line 3 while staying in the current function. Step Into is used when execution reaches line 4 and you want to enter the display(numbers) function, which takes you into the function body starting at line 8. Once inside that function, Step Out continues execution until the current function returns, which is exactly what "step out from line 8" means.
Deactivate breakpoints turns breakpoint handling off so the debugger no longer stops on active breakpoints.
Continue program execution resumes the app until the next breakpoint or until the program finishes.
So the correct control order is:
1 = Continue
2 = Deactivate breakpoints
3 = Step Over
4 = Step Into
5 = Step Out
Review the code snippet.
What is the output from each print statement?
Correct Answer:
Answer the question by typing in the box.
10
Explanation:
This question belongs to Swift Programming Language , specifically the domain covering structs, classes, properties, methods, and the difference between structures and classes .
The key point is that Printer is declared as a class :
class Printer {
var copies: Int
init(copies: Int) {
self.copies = copies
}
}
In Swift, classes are reference types . That means when you assign one class instance to another variable, both variables refer to the same object in memory rather than creating a separate copy. Apple's Swift language guide explains that classes are passed by reference, while structures are value types. So in this code:
var printer1 = Printer(copies: 2)
var printer2 = printer1
both printer1 and printer2 point to the same Printer instance.
Next, this line changes the shared object:
printer2.copies = 10
Because printer2 refers to the same instance as printer1, changing printer2.copies also changes printer1.
copies. Therefore, when the code executes:
print(printer1.copies)
the output is 10 .
This question tests one of the most important Swift concepts: classes are reference types , while structs are value types . If Printer had been a struct instead of a class, the result would have been different because assignment would copy the value rather than share the same instance.
Refer to this image to complete the code.
Note: You will receive partial credit for each correct answer
Correct Answer:

Explanation:
This question belongs to View Building with SwiftUI , especially the objectives for using List views to iterate through collections and structuring views with standard SwiftUI containers. The screenshot shows two grouped sets of rows: one headed MY FRIENDS and one headed MY PETS . In SwiftUI, the correct container for a scrollable table-style presentation of rows is List, and the correct way to divide that list into labeled groups is Section. Apple documents List as a container that presents data in a single-column row- based layout, and Section as a way to organize list content into grouped areas with headers and optional footers. That is exactly the structure shown in the image. ( developer.apple.com , developer.apple.com ) The ForEach(names, id: \.self) and ForEach(pets, id: \.self) lines are already iterating through the arrays, so each ForEach should be wrapped inside a Section. The section labels such as " My Friends " and " My Pets
" are provided with the header: label. So the intended code structure is:
List {
Section {
ForEach(names, id: \.self) { name in Text(name) }
} header: {
Text( " My Friends " )
}
Section {
ForEach(pets, id: \.self) { pet in Text(pet) }
} header: {
Text( " My Pets " )
}
}
This matches the UI shown in the image and aligns directly with SwiftUI list and section composition patterns in App Development with Swift.




